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we know dU = dK
after 2 secs new speed = 20m/s
after 4 sec = 0
and 6sec = 20m/s
therefore,
1/2)v² = gh
or h = (400/20)m. = 20m
h = (1600/20)m = 80m
h = (400/20)m. = 20m
all distances from ground
after 2 secs new speed = 20m/s
after 4 sec = 0
and 6sec = 20m/s
therefore,
1/2)v² = gh
or h = (400/20)m. = 20m
h = (1600/20)m = 80m
h = (400/20)m. = 20m
all distances from ground
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