Question

give answer fast please​

Answer 1

Answer:

9(px-2)

Step-by-step explanation:

Answer 2

Question

Factorise the expression p²-10p+25

what to calculate

We have to factorise this p²-10p+25

Answer

Step by step explanation

p²-10p+25 Here ,we observe that 25 is the square of 5 e.g,=>(5)²=25 so,we can also write 25 as 5²

Rewrite the given equation:-

New Equation : p²-10p+5²

Now,we see that it is in the form of expansion of this identity =>(a-b)²=a²+b²-2ab

Now ,making this expression to this identity

p²-10p+25

Let p be our a and 25 which is 5² be b

=>p²+5²-2(p)(5)=(p-5)²

So,the correct option is (b) (p-5)² ✅

Other Identities:

Other Identity related to this :

$\bold{\boxed{ {(x +y)}^{2} = {x}^{2} + {y}^{2} +2xy}}$

$\bold{\boxed{ {x}^{3} + {y}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)}}$

$\bold{\boxed{(x + y)(x + z) = {x}^{2} + (y+ z)x + yz}}$

$\bold{\boxed{ {(x +y)}^{3} = {x}^{3} + {y}^{3} +3xy[x+y]}}$

$\bold{\boxed{(x + a)(x - b) = {x}^{2} + (a - b)x - ab}}$

$\bold{\boxed{(x - a)(x - b) = {x}^{2} - (a + b)x + ab}}$