Math, asked by glitterzpink2725, 6 days ago

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Answered by nayankanoje6
0

1. 3x-1=14

3x = 14+1 = 15

x = 15/3

x = 5

2.2y = 20

y=20/2

y = 10

3.10+2x=6

2x = 6-10

2x = -4

x = -4/2

x = -2

4. 2μ\5 = 8

2μ = 8*5 = 40

μ = 40/2

μ = 20

5.2x+5 = 14-x

= 14-5

= 9

x = 3

6. x/5+3 = 8

x/5 = 8-3 = 5

x = 5*5

x = 25

7.6x-3 = 15

6x = 15+3 = 18

x = 18/6

x = 3

8. 4m + 2/5 = 1

4m = 1-2/5 = 0.6

m = 0.6/4

m = 0.15

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Answered by nayanborgohain17
0

Answer:

i) x = 5

ii) y = 10

iii) x = 2

iv) z = 20

v) x = 3

vi) x = 25

vii) x = 3

viii) m = 4/3

Step-by-step explanation:

i)

3x -   1= 14

Add 1 to both sides of the equation.

3x - 1 + 1 = 14 + 1

3x = 15

x =  \frac{15}{3}

x = 5

ii)

2y = 20

Divide both sides of the equation by 2

 \frac{2y}{2}  =  \frac{20}{2}

y = 10

iii)

10 - 2x = 6

Subtract 10 from both sides of the equation

10 -10 -  2x  = 6 - 10

 - 2x =  - 4

 - x =  \frac{ -4}{2}

 - x = - 2

x = 2

iv)

 \frac{2z}{5}  = 8

Multiply both sides of the equation by 5

 \frac{2z}{5}   \times 5 = 8 \times 5

2z = 40

z =  \frac{40}{2 }

z = 20

v)

2x + 5 = 14 - x

Subtract 5 from both sides

2x + 5 - 5 = 14 - x - 5

2x = 14 - 5 - x

2x = 9 - x

Move the right hand side x to left side of the equation

2x + x = 9

3x = 9

x =  \frac{9}{3}

x = 3

vi)

 \frac{x}{5}   + 3 = 8

Subtract 3 from both sides

 \frac{x}{5}  + 3 - 3 = 8 - 3

 \frac{x}{5}  = 5

Multiply both sides by 5

 \frac{x}{5}  \times 5 = 5 \times 5

x = 25

vii)

6x - 3 = 15

Add 3 to both sides

6x - 3 + 3 = 15 + 3

6x = 18

x =  \frac{18}{6}

x = 3

viii)

4m +  \frac{2}{5}  = 1

Multiply both sides by 5

4m +  \frac{2}{5}  \times 5 = 1 \times 5

4m + 2 = 5

Subtract 2 from both sides

4 m + 2  -  2= 5 - 2

4m = 3

 m =  \frac{4}{3}

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