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in isoceleus triangle, let the base angles be x
The vertex angle = x/2
Therefore, x + x+ x/2 = 180°
or, 5x/2 = 180°
or, x = 180*2/5
or, x = 72°
So, angles are 72°, 72°, (base angles) & 36° (vertex angle that is half of base angle.
The vertex angle = x/2
Therefore, x + x+ x/2 = 180°
or, 5x/2 = 180°
or, x = 180*2/5
or, x = 72°
So, angles are 72°, 72°, (base angles) & 36° (vertex angle that is half of base angle.
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