Question

give answer it's urgent​

Answer 1

Answer:

∠AEB=90°.

Step-by-step explanation:

If ∠E=90° .

Then, ∠AEB+∠E=180° (linear pair).

So, ∠AEB+90°=180°.

∠AEB=180°-90°.

∠AEB=90°.

Hope it is helpful for you...........

Answer 2

Answer:

/_ AEB = 70°

Step-by-step explanation:

As we know that when there are two parallel lines and a transversal cuts these two lines then their interior opposite angles are equal

Thus /_DCB = /_CBA --------(according to the given diagram)

Then /_ EBA = 60°

and /_EAB = 50° (given)

Here we can see that EAB is a ∆

Then, sum of all its angle = 180°

Then,

/_ AEB + /_EBA + /_EAB = 180°

=> /_ AEB + 50° + 60° = 180°

=> /_ AEB + 110° = 180°

=> /_ AEB = 180° – 110°

=> /_ AEB = 70°

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