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If first term of an A.P. is a, second term is b and last term is c, then show that sum
of all terms is
(a+c)(b+c-2a)÷2(b-a)
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a = a
second term =b
last term tn = c
D (common difference )=b-a
tn = a+(n-1)d
c =a+(n-1)(b-a)
c = a+bn -a
c =bn
c /b =n
sm = n/2( a+l)
sm = c/b/2(a+c)
second term =b
last term tn = c
D (common difference )=b-a
tn = a+(n-1)d
c =a+(n-1)(b-a)
c = a+bn -a
c =bn
c /b =n
sm = n/2( a+l)
sm = c/b/2(a+c)
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