give answer of both questions .
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2.
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As 75°and z forms linear pair,
75°+z=180°
Z=180°-75°=105°.....
As DC is parallel to AB,
X=75°(corresponding angles).....
Also in quadrilateral ABCD, sum of all angles=360°=>z+z+x+y=360°
=>y=360°-(2×105°+75°)=360°-290°
=>y=70°...
75°+z=180°
Z=180°-75°=105°.....
As DC is parallel to AB,
X=75°(corresponding angles).....
Also in quadrilateral ABCD, sum of all angles=360°=>z+z+x+y=360°
=>y=360°-(2×105°+75°)=360°-290°
=>y=70°...
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