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dilute sulphuric acid will displace the copper from plate and the solution will form is copper sulphate
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9a) ●when dil. H2SO4 is poured on copper plate then a chemical reaction is formed producing copper sulphate ( blue aqueous solution ) and hydrogen .
H2SO4 + Cu → CuSO4 + H2
b) ● Iron nails are placed in Copper sulphate solution which forms Iron sulphate and Copper acts as a black residual precipitate .
Fe + CuSO4 → FeSO4 + Cu ↓ [precipitate]
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H2SO4 + Cu → CuSO4 + H2
b) ● Iron nails are placed in Copper sulphate solution which forms Iron sulphate and Copper acts as a black residual precipitate .
Fe + CuSO4 → FeSO4 + Cu ↓ [precipitate]
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