Question

give answer of this
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Answer 1

In △ABC and △DEF

∠BAC = ∠EDF ...given

AB = DE ...given

DF = AC ..given

•°• △ABC is congruent to △DEF .. SAS test

c.s.c.t (corresponding sides of congruent triangle) :

AB = DE, AC = DF, BC = EF

c.a.c.t (corresponding angles of congruent triangle):

∠A =∠D, ∠B = ∠E, ∠C = ∠F

Answer 2

Given: AB = DE, ∠BAC = ∠EDF and AC = DF.

In ∆ABC and ∆DEF,

AB = DE (given)

∠BAC = ∠EDF (given or same angle)

AC = DF (given)

Therefore, ∆ABC ≅ ∆DEF (By SAS criterion)

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