Question

give answer of this question

Answer 1

PLZ MARK AS BRAINLIEST
[tex] 3^{x+y} = 3^{4} [/tex]   (coz 81= 3×3×3×3)
therefore x+y=4
now
$81^{x-y} = 3^{1}$
now replace 81 by 3 raised to 4
$3^{4(x-y)}= 3^{1}$
therefore 4x-4y=1
Let's solve your system of equations by elimination.x+y=4;4x−4y=1Steps:Multiply the first equation by -4,and multiply the second equation by 1.−4(x+y=4)1(4x−4y=1)Becomes:−4x−4y=−164x−4y=1Add these equations to eliminate x:−8y=−15Then solve−8y=−15for y:−8y−8=−15−8(Divide both sides by -8)y=15/8Now that we've found y let's plug it back in to solve for x.Write down an original equation:x+y=4Substitute15/8in x+y=4:x+15/8=4x+15/8+−15/8=4+−15/8(Add (-15)/8 to both sides)x=17/8
x=17/8 and y=15/8