Question

give answer of this question class 9​

Answer 1

Answer

Given,

x=3+2√2

Inverse equation,

1/x=1/3+2√2

=>1/x=(3–2√2){(3+2√2)(3–2√2)}

=>1/x=(3–2√2)/{(3)²-(2√2)²}

=>1/x=(3–2√2)/(9–8)

=>1/x=(3–2√2)/1

=>1/x=3–2√2

=>x+1/x=3+2√2+3–2√2

=>x+1/x=6

=>x²+1/x²=(x+1/x)² -2.x.1/x

=>x²+1/x² =(6)²-2

=>x²+1/x²=36–2

=>x²+1/x²=34

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Answer 2

Answer:

Step-by-step explanation:

x=3-2√2 ,1/x= 3+2√2

Then x²+1/x²=(3-2√2)²+(3+2√2)²

= 9- 12√2+8+9+12√2+8

=34

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