give answer please question no. 16, 17, ,18, 19, 20
Answers
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16. Given that
x = 2 + √3
1/x = 1/2 + √3
= 1 × (2 - √3)/(2 + √3) (2 - √3)
= (2 - √3)/(2^2 - √3^2)
= (2 - √3)/4 - 3
= (2 - √3)
Therefore ,
x^2 = (2 + √3)
= (2)^2 + (√3)^2 + 2 × 2 × √3
= 4 + 3 + 4√3
= 7 + 4√3
1/x^2 = (2 - √3)^2
= (2)^2 + (√3)^2 - 2 × 2 × √3
= 4 + 3 - 4√3
= 7 - 4√3
x^2 + 1/x^2
= (7 + 4√3) + (7 - 4√3)
= 7 + 4√3 + 7 - 4√3
= 7 + 7 + 4√3 - 4√3
= 14
17. x^4+4
=(x^2)^2 +(2)^2
=(x^2+2)^2
=(x^2+2) (x^2 +2)
18.. Volume of sphere = 4/3 π R*(3)
Here R = 2r
Volume of sphere = 4/3 π (2r)*3
Volume =( 4/3 )8π r*(3)
Volume of sphere = 32/3 π r*3
OR
Volume of cuboid=444cm3
Area of base =lb=88cm2
Height=??
Volume of cuboid=lbh
440=88h
h=5cm
19. The angle sum of a quadrilateral is (4-2)x 180=360
The sum of all the angles of the quadrilateral =95 +70+110+80=355
Since the angle sum is not equal to 360degree. therefore they cannot be the angles of a quadrilateral.
20. The equation intersect s axis so y coordinate will be 0
so x = ?
y =0
2x +3y = 6
2x +3*0 = 6
2x = 6
x =3
coordinate is (3,0)
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