Question

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Answer 1

Answer:

question no. 17= (a) The image distance is 12 cm

(b) The image size is 5 cm

(c) The magnification produced is 2 cm

question no 18 = (- 1.6 m )

Explanation:

object distance , u = -6

height of the object , h1 =2.5 cm

focal length (f) = 4cm

using mirror formula :-

= 1/u = 1/4-1/6

= 1/u=1/12

= u = 12 cm

Therefore, the image distance is 12 cm

magnification formula :-

m=u/u

=m=12/-6

=m=-2

thus, the magnification is 2

The negative sign represents image formed is real and inverted

Again we have

M=h2/h1

-2= h2/2.5

h2= -5

question no. 18

we have u = 0.8 and m=2/3 so m=v/ u = h2/h1

I/f = 1 / v - 1/ u

so, the focal length become

= (-1.6 m

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