Question

give answer


solve part ii​

Answer 1

In ΔAOB & ΔAOC,

AB = AC (Given)

∠OBA= ∠OCA (from eq1)

OB = OC. (from eq 2)

Therefore, ΔAOB ≅ ΔAOC

( by SAS congruence rule)

Then,

∠BAO = ∠CAO

(by CPCT)

So, AO is the bisector of ∠BAC.

Answer 2

In ΔAOB & ΔAOC,

AB = AC (Given)

∠OBA= ∠OCA (from eq1)

OB = OC. (from eq 2)

Therefore, ΔAOB ≅ ΔAOC

( by SAS congruence rule)

Then,

∠BAO = ∠CAO

(by CPCT)

So, AO is the bisector of ∠BAC.