Question

Give answer with explaination please

Answer 1

Answer:

The equation to the normal at t1 on the parabola

y²=4bx is

y+xt1=2bt1+bt1³→(1)

If equation (1) passes through (bt2²,2bt2)

2bt2+bt2²t1=2bt1+bt1³

2b(t2-t1)=bt1(t1²-t2²)

-2b(t1-t2)=bt1(t1-t2)(t1+t2)

-2=t1(t1+t2)

-2/t1-t1=t2

t2=-t1-2/t1

Step-by-step explanation:

Hope it helps you.......