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f1+ f2 + f3 = 6 i +2j + 6k
s= (-2-1)i + ( -2 +1) j +(-4 -2)k
= -3 i -j -6k
As work = f. s
= (6 i + 2j + 6k). ( -3 i -j -6k)
= 6× -3 + 2× -1 + 6× -6
= -18 -2 -36
= -56 J
s= (-2-1)i + ( -2 +1) j +(-4 -2)k
= -3 i -j -6k
As work = f. s
= (6 i + 2j + 6k). ( -3 i -j -6k)
= 6× -3 + 2× -1 + 6× -6
= -18 -2 -36
= -56 J
shubhamgupta339:
thnxxx brother
Answered by
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ANsWER.
WOrk done by the net force =56joule
SOLUTION
LOOK IN ATTACHMENT
DIGRAM
LOOK IN ATTACHMENT
FORMULA
Work done=force×displacement
WOrk done by the net force =56joule
SOLUTION
LOOK IN ATTACHMENT
DIGRAM
LOOK IN ATTACHMENT
FORMULA
Work done=force×displacement
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thank uhh sooooo much
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