give answere w
quetion no.19
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Speed is x km/h
Let time taken for onward distance be t
Speed=distance/time
Time =distance/speed
t=400/x
On return journey
Time for return journey e t'
Speed will become( x+40)km/h
t'=400/(x+40)
t'=t-30
Let time taken for onward distance be t
Speed=distance/time
Time =distance/speed
t=400/x
On return journey
Time for return journey e t'
Speed will become( x+40)km/h
t'=400/(x+40)
t'=t-30
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