Question

give ANSWERS and reason too ​

Answer 1

$\boxed{\rm{\color{#ff99ff}{Power (P)= \frac{Potential \: Difference(V)}{Resistance(R)}}}}$

• Resistance is fixed. So, R=R'
• Potential difference is halfed in second case. So, V÷2 = V'

$\rm P' = \frac{V'}{R'} = \frac{ \frac{V}{2} }{R}$

$\rm P' = \frac{V}{2R}$

$\rm \frac{P}{P'} = \frac{ \frac{V}{R} }{ \frac{V}{2R} } = \frac{1}{2}$

$\rm P' = 2P$

New Power(P') will become $\sf \red{(a)~double}$.

Answer 2

$\boxed{\rm{\color{gray}{Power (P)= \frac{Potential \: Difference(V)}{Resistance(R)}}}}$

1. Resistance is fixed. So, R1=R2
2. Potential difference is halved in second case. So, V1÷2 = V2

$\rm P2 = \frac{V2}{R2} = \frac{ \frac{V1}{2} }{R1}$

$\rm P2 = \frac{V1}{2×R1}$

$\rm \frac{P1}{P2} = \frac{ \frac{V1}{R} }{ \frac{V1}{2×R1} } = \frac{1}{2}$

$\rm P2 = 2×P1$

New Power(P2) will become$\sf \red{(a)~double}$