Give answers for chemistry. Acetic acid get ionised 1.3% in decimolar solution. What is ionisation constant ??? Answer ts .....plz
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Ionisation constant Ka = a^2*c(1-a)
where a is the degree of dissociation
c is the concentration
Here a= 1.3% = 0.013
c = 0.1M
Substituting the values we get,
Ka = 1.7*10^-3
where a is the degree of dissociation
c is the concentration
Here a= 1.3% = 0.013
c = 0.1M
Substituting the values we get,
Ka = 1.7*10^-3
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