give at least 8 applications of pressure
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* LPG gas Is stored under high pressure
*some kind of pressure is needed for the pumping of blood
*filling gas in the balloons and tyres
*we also apply some pressure while printing and writting
*we give pressure when we squeeze out the cloths to make them dry.
*Pressure cookers apply pressure for the faster cooking of food
*we give out some pressure in some daily activities like pinning the notice ,writing with a chalk in the black board etc
*some kind of pressure is needed for the pumping of blood
*filling gas in the balloons and tyres
*we also apply some pressure while printing and writting
*we give pressure when we squeeze out the cloths to make them dry.
*Pressure cookers apply pressure for the faster cooking of food
*we give out some pressure in some daily activities like pinning the notice ,writing with a chalk in the black board etc
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Daily Life Pressure and Its Application
The application of atmospheric pressure, or in simple words, air pressure is referred to as the numerous activities that we do or observe every day without a realization of any kind of push or pressure. We are able to survive this high-pressure condition as we have evolved and somewhere managed our body functions withstand this amount of high pressure.
Solved Example for You on Pressure and Its Application
Question. What is the excess pressure inside a bubble of soap solution of radius 5.00 mm, given that the surface tension of soap solution at the temperature (20 °C) is 2.50 × 10–2 N m–1? If an air bubble of the same dimension were formed at depth of 40.0 cm inside a container containing the soap solution (of relative density 1.20), what would be the pressure inside the bubble? (1 atmospheric pressure is 1.01 × 105 Pa).
Solution: Excess pressure inside the soap bubble is 20 Pa;
Soap bubble is of radius, r = 5.00 mm = 5 × 10–3 m
The surface tension of the soap solution, S = 2.50 × 10–2 Nm–1
A relative density of the soap solution = 1.20
Density of the soap solution, ρ = 1.2 × 103 kg/m3
Air bubble formed at a depth, h = 40 cm = 0.4 m
Radius of the air bubble, r = 5 mm = 5 × 10–3 m
1 atmospheric pressure = 1.01 × 105 Pa
Acceleration due to gravity, g = 9.8 m/s2
Hence, the excess pressure inside the soap bubble is:
P=4S/r
=(4×2.5×10-2)/5×10-3
=20Pa
Therefore, the excess pressure inside the soap bubble is 20 Pa. The excess pressure inside the air bubble is :
P’=2S/r
=(2×2.5×10-2)/5×10-3
=10Pa
Therefore, the excess pressure inside the air bubble is 10 Pa. At a depth of 0.4 m, the total pressure inside the air bubble,
Atmospheric pressure + hρg + P’
=1.01×105+0.4×1.2×103x9.8+10
=1.057×105Pa
=1.06×105Pa
Therefore, the pressure inside the air bubble is 1.06×105 Pa.
This concludes our discussion on the topic of pressure and its application.
The application of atmospheric pressure, or in simple words, air pressure is referred to as the numerous activities that we do or observe every day without a realization of any kind of push or pressure. We are able to survive this high-pressure condition as we have evolved and somewhere managed our body functions withstand this amount of high pressure.
Solved Example for You on Pressure and Its Application
Question. What is the excess pressure inside a bubble of soap solution of radius 5.00 mm, given that the surface tension of soap solution at the temperature (20 °C) is 2.50 × 10–2 N m–1? If an air bubble of the same dimension were formed at depth of 40.0 cm inside a container containing the soap solution (of relative density 1.20), what would be the pressure inside the bubble? (1 atmospheric pressure is 1.01 × 105 Pa).
Solution: Excess pressure inside the soap bubble is 20 Pa;
Soap bubble is of radius, r = 5.00 mm = 5 × 10–3 m
The surface tension of the soap solution, S = 2.50 × 10–2 Nm–1
A relative density of the soap solution = 1.20
Density of the soap solution, ρ = 1.2 × 103 kg/m3
Air bubble formed at a depth, h = 40 cm = 0.4 m
Radius of the air bubble, r = 5 mm = 5 × 10–3 m
1 atmospheric pressure = 1.01 × 105 Pa
Acceleration due to gravity, g = 9.8 m/s2
Hence, the excess pressure inside the soap bubble is:
P=4S/r
=(4×2.5×10-2)/5×10-3
=20Pa
Therefore, the excess pressure inside the soap bubble is 20 Pa. The excess pressure inside the air bubble is :
P’=2S/r
=(2×2.5×10-2)/5×10-3
=10Pa
Therefore, the excess pressure inside the air bubble is 10 Pa. At a depth of 0.4 m, the total pressure inside the air bubble,
Atmospheric pressure + hρg + P’
=1.01×105+0.4×1.2×103x9.8+10
=1.057×105Pa
=1.06×105Pa
Therefore, the pressure inside the air bubble is 1.06×105 Pa.
This concludes our discussion on the topic of pressure and its application.
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