Give chemical equation 1)2-methyl propene is irradiated with HBr in presence of benzoyl peroxide.
2)2-butene is heated with alkaline KMnO4
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1. When two methyl propene is irradiated with HBr in the presence of benzoyl peroxide then according to Marconikows rule product will be 2 bromo 2 methyl propane:
Equation 1 see on image
Benzoyl peroxide is used in skin treatment. It help in reducing the amount of acne-causing bacteria and by causing the skin to dry.
2. When 2 butene is heated with hot alkaine KMnO4 then the product will be 2 molecules of ethanoic acid:
CH_{3} -CH=CH-CH_{3} {Hot Alkaline KMnO_{4}/OH }_{----->} 2CH_{3} COOH[/tex]
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- When 2-Methyl propene is reacted with HBr in the presence of benzoyl peroxide, 1-Bromo-2-methyl propane is obtained as the major product. The reaction follows anti-Markonivov's rule because of the presence of peroxide molecule in the reaction.
- When 2-butene is treated with alkaline KMnO₄, it undergoes oxidation reaction and the product obtained is an enantiomeric mixture of vicinal diol, i.e., ± 2,3-Dihydroxybutane.
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