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(1)
Given x + y = -4.
On cubing both sides, we get
= > (x + y)^3 = (-4)^3
= > x^3 + y^3 + 3xy(x + y) = -64
= > x^3 + y^3 + 3xy(-4) = -64
= >x^3 + y^3 - 12xy + 64 = 0.
Therefore the value of x^3 + y^3 - 12xy + 64 = 0.
(2)
Given x = 2y + 6
On cubing both sides, we get
= > x^3 = (2y + 6)^3
= > x^3 = 8y^3 + 216 + 3 * 2y * 6(2y + 6)
= >x^3 - 8y^3 + 216 + 36y(x)
= > x^3 - 8y^3 - 216 - 36xy = 0.
Therefore x^3 - 8y^3 - 216 - 36xy = 0.
Hope this helps!
Given x + y = -4.
On cubing both sides, we get
= > (x + y)^3 = (-4)^3
= > x^3 + y^3 + 3xy(x + y) = -64
= > x^3 + y^3 + 3xy(-4) = -64
= >x^3 + y^3 - 12xy + 64 = 0.
Therefore the value of x^3 + y^3 - 12xy + 64 = 0.
(2)
Given x = 2y + 6
On cubing both sides, we get
= > x^3 = (2y + 6)^3
= > x^3 = 8y^3 + 216 + 3 * 2y * 6(2y + 6)
= >x^3 - 8y^3 + 216 + 36y(x)
= > x^3 - 8y^3 - 216 - 36xy = 0.
Therefore x^3 - 8y^3 - 216 - 36xy = 0.
Hope this helps!
siddhartharao77:
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Answered by
1
Hi,
Please see the attached file!
Thanks
Please see the attached file!
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