Question

Give correct answer and I will mark your name as brain list

Answer 1

★Hi ,there !!★



here is your answer !!


10 ) x - 1 is factor ,



p ( x ) = 4x³ + 3x² -4x + K ---------------- eq (1)



x -1 = 0


x = 1



and ,


on putting the value of of x in equation 1 we get


4 (1)³ + 3(1)² -4× 1 + K = 0

=> 4 + 3 -4 + k = 0



=> k = -3


11 )


x -a = 0


x = a


p(x ) = x³ -ax² + 2x +a -1 ---------------- eq (1)



on putting the value of x in equation 1


we get



a³-a³ + 2a + a -1 = 0


=> 3a = 1


a= 1 / 3



hope it help you dear !!!




thanks !!!



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Answer 2

10.
p(x)=4x^3+3x^2-4x+k
as it is given that
x-1 is a factor of p(x)
then by remainder method
x=1
p(1)=4(1)^3+3(1)^2-4(1)+k
=4+3-4+k
=3+k
=>-3=k.
11)p(x)=x^3-ax^2+2x+a-1
as it is given that
x-a is a factor of p(x)
by remainder method
x=a
p(a)=a^3-a^3+2a+a-1
=3a-1
=>a=1/3
hope my answer helped you.