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Answer:
- 320.5 kPa is the new pressure of the ideal gas after the compression in volume by a factor of 3 .
Explanation:
An ideal gas follows: P V = n R T
or P₁ V₁ / T₁ = P₂ V₂ /T₂
So P₂ = P₁ V₁ T₂ / (T₁ V₂)
Given P₁ = 100 kPa , V₁ = 15 ml = 15 * 10⁻⁶ m³, T₁ = 293⁰K , T₂ = 313⁰K, V₂= 5 * 10⁻⁶ m³.
V₁ = 3 V₂V₂
P₂ = 100 *10³ * 3 * 313/293 = 3.205 * 10⁵ Pa
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