Question

give correct answer with explanation !!

Answer 1

Thanks, bro for this question.

We know that,

1 Kelvin (K) = - 273 °C

The boiling point of the gas is 80 °C.

Let me give you the relation :
$t_{c} = t_{k} - 273 \\ \\ = > t_{k} = t_{c} + 273 \\ \\ = > t_{k} = - 80 + 273 = 193 \\ \\ where \: \: t_{c} \: \: and \: \: t_{k} \: \: are \: \: degree \: \: \\ celcius \: \: and \: \: kelvin \: \: temeratures \\ respectively.$

Thus,

- 80 °C = 193 K

So, the boiling temperature of the gas is equivalent to 193 K (Option B).

Thank you for your question.

Answer 2

the answer is option b 193k

thanks

hope it helps