Question

give electron dot structure of mgo​

Answer 1

$\huge\mathcal{ PLZ FOLLOW \: ME}$

Answer 2

Elemental magnesium has 12 nuclear protons,  

Z

=

12

. It has 2 valence electrons that are conceived to be lost when it undergoes oxidation to  

M

g

2

+

.

M

g

→

M

g

2

+

+

2

e

−

 

(

i

)

Elemental (atomic!) oxygen has 8 electrons,  

Z

=

8

. The oxide anion thus has 10 electrons upon reduction:

O

+

2

e

−

→

O

2

−

 

(

i

i

)

So  

(

i

)

+

(

i

i

)

=

M

g

(

s

)

+

1

2

O

2

(

g

)

→

M

g

O

(

s

)