Question

give equation of path of projectile and time of maximum height​

Answer 1

Answer:

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Answer 2

Answer:

the equation of projectile is ,

       $Y = (tan \theta) X - \frac {gX^{2} } {2 ( v cos \theta )^2 }$

and time of maximum height ,

        $T_{m} =\frac{ v_{o} sin\theta}g$