Question

give example for a reaction in which kp > ke​

Answer 1

In this case, you have 2 moles of gas on the products' side and 5 moles of gas on the reactants side → Kp≠Kc . Since you have 2 moles of gas on both sides of the equilibrium, you will indeed get Kp=Kc

Plz mark my answer as BRAINLIEST

Answer 2

Answer:

K

p

=K

c

(RT)

Δn

If Δn=0,K

p

=K

c

If Δn>0,thenK

p

>K

c

If Δn<0,thenK

p

<K

c

For the reaction: H

2

(g)+Cl

2

(g)⇌2HCl

(

g)

Δn is the number of moles of gaseous products - number of moles of gaseous reactants in a balanced equation.

Δn=2−(1+1)=0

∴K

p

=K

c

Explanation:

$\huge\text{ғᴏʟʟᴏᴡ ᴍᴇ}$

$\Large\text{❥PaLaK}$