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two chords ab and CD of a circle intersect each other at outside the circle if ab is equal to 6 cm and b p is equal to 2 cm and BD is equal to 2.5 cm find CD​

Answer 1

Answer:

It is given that AB and CD of a circle intersect each other at P outside the circle. If AB = 6cm, BP = 2cm and PD = 2.5cm So we get AP × BP = CP × DP From the figure we know that CP = CD + DP By substituting the values 8 × 2 = (CD + 2.5) × 2.5 cm Consider x = CD So we get 8 × 2 = (x + 2.5) × 2.5 On further calculation 16 = 2.5x + 6.25 It can be written as 2.5x = 16 – 6.25 By subtraction 2.5x = 9.75 By division x = 9.75/2.5 So we get x = 3.9cm Therefore, CD = 3.9cm.

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