Question

give explanation for this ​

Answer 1

$\displaystyle\sf{Given\:,$

• $\displaystyle\sf{R_0=10\:\Omega$

• $\displaystyle\sf{T_i=20^o\:C$

• $\displaystyle\sf{T_f=100^o\:C$

• $\displaystyle\sf{\alpha=0.004\:/\:^oC$

$\boxed{\displaystyle\sf{R_1=R_0[1+\alpha (T_f-T_i)]}}$

$\displaystyle\sf{Applying\:the\:values\:to\:the\:equation\:,$

$\implies\displaystyle\sf{R_1=10[1+0.004(100-20)]$

$\implies\displaystyle\sf{R_1=10[1+(0.004\times80)]$

$\implies\displaystyle\sf{R_1=10[1+0.32]$

$\implies\displaystyle\sf{R_1=[10\times1.32]$

$\implies\displaystyle\sf{R_1=13.2\:\Omega$

$\displaystyle\sf{As\:the\:temperature\:increases\:the\:resistance\:of\:the\:wire\:also\:increases\:.$

Answer 2

Answer:

Thanks mahira...

nee romba nalla Friend

Thanks for the understanding

thank you thank you thank you