Math, asked by hazel1279, 8 months ago

give explanation pls​

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Answers

Answered by CuteAnswerer
0

SOLUTION :

  • 1)

 \longrightarrow\sf 2x^2+x-a=5\\

  • Substitute the value of x :

 \longrightarrow\sf 2 (0)^2+0-a=5\\ \\

 \longrightarrow\sf 2\times 0+0 - a = 5 \\ \\

 \longrightarrow\sf 0+0 - a = 5 \\ \\

 \longrightarrow\sf 0+0 -5 = a \\ \\

 \longrightarrow\sf -5 = a \\ \\

\longrightarrow{\underline{\boxed{\pink{\bf a=-5 }}}}

  • 2)

 \longrightarrow\sf p-(p-q)-q-(q-p)\\ \\

 \longrightarrow\sf p-p+q-q-q+p\\ \\

 \longrightarrow\sf p+p-p+q-q-q\\ \\

 \longrightarrow\sf 2p-p+q-2q\\ \\

 \longrightarrow\underline {\boxed{\pink{\bf{ p-q}}}}\\ \\

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