Question

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Answer 1

Answer:

₹ 49680

Step-by-step explanation:

COST OF PAINTING = AREA X COST PER METER

AREA = L X B

LENGTH = 24

BREADTH = 18

AREA = 24 X 18

          = 432

COST PER METER = 115 sq.m

COST OF PAINTING = 432 X 115

                                  = ₹ 49680

HOPE IT IS HELPFUL !!!

Answer 2

$\Large{\underbrace{\underline{\sf{Understanding\;the\; Question}}}}$

Here in this question, concept of area of rectangle is used. We are given length and breadth of rectangular ply board and we have to find the cost of painting it. The cost of one m² is also given as ₹115. To find the cost of painting the whole board, we have to multiply the total area of board with cost per m².

So let's do it!!

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Given:

• Length of rectangular cardboard=24m

• Breadth of rectangular cardboard=18m

• Cost of m²=₹115

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To find:

• Cost of painting whole cardboard

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Formula used:

• Area of rectangle=Length×Breadth

___________________________.

Solution:

Area of cardboard=Length×Breadth

Area of cardboard=24m×18m

Area of cardboard=432m²

We have find area of cardboard.

Now let's find cost of painting!!

___________________________

Cost of painting 1 m² of cardboard=₹115

Cost of painting 432m² of cardboard=₹115×432

Cost of painting the cardboard=₹49,680.

So the required cost is ₹49,680.

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Additional information:

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

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