Question

give fast plzzz explanation​

Answer 1

Explanation:

Answer is the lengthy but answered is 220 volt current

Answer 2

Answer:

$\bold\red{\frac{3}{\sqrt{2}}\:Ampere}$

Explanation:

It is being given that,

An alternating e.m.f. ,

$e = 300 \sin(100\pi \: t)$

To find :

r.m.s current

Solution:

We know that,

r.m.s means root mean square in which the quantity is first squared, then its mean is to be found and at last its square root .

Therefore,

According to the definition of r.m.s,

we have,

${e}^{2} = {(300)}^{2} { \sin}^{2} (100\pi \: t)$

Now,

it's mean is,

$< {e}^{2} > = {(300)}^{2} < { \sin }^{2} (100\pi \: t) > \\ \\ where \\ \\ \bold{< \: \: > \: denotes \: mean \: value}$

But,

We already know that,

$< { \sin }^{2} (wt) > = \frac{1}{2}$

Thus,

Putting the values,

we get,

$= > < {e}^{2} > = \frac{ {(300)}^{2} }{2} \\ \\ = > \sqrt{ < {e}^{2} > } = \sqrt{ \frac{ {(300)}^{2} }{2} } \\ \\ = > \sqrt{ < {e}^{2} > } = \frac{300}{ \sqrt{2} }$

But,

we know that,

$\bold{\sqrt{ < {e}^{2} > } = e_{rms} \: }$

Therefore,

we get,

$= > e_{rms} = \frac{300}{ \sqrt{2} }$

Niw,

it's being given that,

$Resistance, \:R = 100 \:Ω$

But,

we know that,

$\bold{\frac{e_{rms}}{R}=i_{rms}}$

Therefore,

we get,

$= > i_{rms} = \frac{ \frac{300}{ \sqrt{2} } }{100} \\ \\ = > i_{rms} = \frac{3}{ \sqrt{2} }$

Hence,

$\bold{r.m.s\:current=\frac{3}{\sqrt{2}}\:Ampere}$