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Given Equation is a + b + c = 0
= > a + b = -c ------ (1)
Now,
On cubing both sides, we get
= > (a + b)^3 = (-c)^3
= > a^3 + b^3 + 3ab(a + b) = -c^3
= > a^3 + b^3 + 3ab(-c) = -c^3
= > a^3 + b^3 - 3abc = -c^3
= > a^3 + b^3 + c^3 = 3abc.
Therefore the value of a^3 + b^3 + c^3 = 3abc.
Hope this helps!
= > a + b = -c ------ (1)
Now,
On cubing both sides, we get
= > (a + b)^3 = (-c)^3
= > a^3 + b^3 + 3ab(a + b) = -c^3
= > a^3 + b^3 + 3ab(-c) = -c^3
= > a^3 + b^3 - 3abc = -c^3
= > a^3 + b^3 + c^3 = 3abc.
Therefore the value of a^3 + b^3 + c^3 = 3abc.
Hope this helps!
Anonymous:
he was given answe in algebraic form
My answer is correct.u can ask anyone
I know u are right siddartharo
which one was correct
both are correct in their own
ways
but where is your value it should come = 0
my answer is correct
This is not the correct way to do this solution
what will be the answer
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Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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