give full solution.
Attachments:
Answers
Answered by
1
Given Equation is a + b + c = 0
= > a + b = -c ------ (1)
Now,
On cubing both sides, we get
= > (a + b)^3 = (-c)^3
= > a^3 + b^3 + 3ab(a + b) = -c^3
= > a^3 + b^3 + 3ab(-c) = -c^3
= > a^3 + b^3 - 3abc = -c^3
= > a^3 + b^3 + c^3 = 3abc.
Therefore the value of a^3 + b^3 + c^3 = 3abc.
Hope this helps!
= > a + b = -c ------ (1)
Now,
On cubing both sides, we get
= > (a + b)^3 = (-c)^3
= > a^3 + b^3 + 3ab(a + b) = -c^3
= > a^3 + b^3 + 3ab(-c) = -c^3
= > a^3 + b^3 - 3abc = -c^3
= > a^3 + b^3 + c^3 = 3abc.
Therefore the value of a^3 + b^3 + c^3 = 3abc.
Hope this helps!
Anonymous:
he was given answe in algebraic form
Answered by
3
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
Attachments:
Similar questions
Political Science,
7 months ago
Math,
7 months ago
Accountancy,
7 months ago
Chemistry,
1 year ago
Math,
1 year ago
Math,
1 year ago
Math,
1 year ago