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4 images are there swip left you will get the fourth image
Step-by-step explanation:
2)
x^(3)-3x^(2)-9x-5
Let p(x)=x^(3)-3x^(2)-9x-5
By trial we find that
p(-1)=(-1)^(3)-3(-1)^(2)-9(-1)-5
=-1-3+9-5=0
:. By Factor Theorem x-(-1) i.e. (x+1) is a factor of p(x)
Now
x^(3)-3x^(2)-9x-5
=x^(2)(x+1)-4x(x+1)-5(x+1)
=(x+1)(x^(2)-4x-5)
=(x+1)(x^(2)-5x+x-5)
=(x+1){x(x-5)+1(x-5)}
=(x+1)(x-5)(x+1)
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