give give me the answer fast trigonometry ratio of complementary angle
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iii. 2sin^2 63+2sin^2 27+1 / 3cos^2 17+3cos^2 73-2
2(sin^2 63+sin^2 27)+1 / 3(cos^2 17 +cos^2 73 -2
2(sin^2 63+cos^2 63)+1 / 3(cos^2 17+sin^2 17-2
2(1)+1 / 3(1)-2
2+1 / 3-2
3/1
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Answer :
Sec²Ф - cot²(90 - Ф)/[cosec²67 - tan²23] + (sin²40 + sin²50)
⇒ sec²Ф - tan²Ф/[cosec²67 - cot²67] + (sin²40 + cos²(90 - Ф))
⇒ 1/1 + 1
⇒ 2
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