Give identity of (a+b+c)^2
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Here is your answer dear⬇️
Let (b + c) = x
Then (a + b + c)² = (a + x)² = a² + 2ax + x²
= a² + 2a (b + c) + (b + c)²
= a² + 2ab + 2ac + (b² + c² + 2bc)
= a² + b² + c² + 2ab + 2bc + 2ca
Therefore, (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
Let (b + c) = x
Then (a + b + c)² = (a + x)² = a² + 2ax + x²
= a² + 2a (b + c) + (b + c)²
= a² + 2ab + 2ac + (b² + c² + 2bc)
= a² + b² + c² + 2ab + 2bc + 2ca
Therefore, (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
Answered by
2
Hii
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
hope it will help you
plzz mark me as brainliest
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
hope it will help you
plzz mark me as brainliest
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