Give : In quadrilateral ABCD ,angl C =64 ,angle D=angle C =8 ;Angle A =5(a+2) and angle B =2 ( 2a + 7,)°. Calculate angle A .Plz help I have exam today
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We know that sum of all angles of quad is 360
So
64 +(64-8)+5 (a+2)+2 (2a+7) = 360
64 + 56 + 5a + 10 + 4a +14 = 360
64 + 56 + 9a + 24 = 360
144+ 9 a = 360
9a = 360 - 144
a = 216/ 9
a = 24 Ans
hope it help you...
So
64 +(64-8)+5 (a+2)+2 (2a+7) = 360
64 + 56 + 5a + 10 + 4a +14 = 360
64 + 56 + 9a + 24 = 360
144+ 9 a = 360
9a = 360 - 144
a = 216/ 9
a = 24 Ans
hope it help you...
arshad4286:
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