Question

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hey guys tc of yourself im leaving the app my i D will be handeled by mine friend Rohan​

Answer 1

ok

Appropriate Question:

The denominator of a rational number is greater than its numerator by 7. If the numerator is increased by 17 and denominator is decreased by 6, the new number formed becomes 2. Find the original number.

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Given: The denominator of a rational number is greater than its numerator by 7.

❒ Let the numerator be x. And, the Denominator be (x + 7).

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$\qquad\quad\boxed{\bf{\mid{\overline{\underline{\bigstar\: According\: to \; the\; Question \: :}}}}\mid}$

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If the numerator is increased by 17 and denominator is decreased by 6, the new number formed becomes 2.

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Therefore,

Numerator, x = (x + 17)

Also,

Denominator, (x + 7 - 6) = (x + 1)

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Now,

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$:\implies\sf \dfrac{\Big(x + 17 \Big) }{\Big(x + 1 \Big)} = 2 \\\\\\:\implies\sf \Big(x + 17 \Big) = 2 \Big(x + 1 \Big) \\\\\\:\implies\sf x + 17 = 2x + 2\\\\\\:\implies\sf 2x - x = 17 - 2\\\\\\:\implies{\underline{\boxed{\frak{\pink{x = 15}}}}}\;\bigstar$

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Hence,

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Numerator, x = 15

And, Denominator, (x + 7) = 15 + 17 = 22

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$\therefore{\underline{\sf{Hence, \: the\; original\; number\;is \; \bf{\dfrac{15}{22}}.}}}$

Answer 2

ok I will wait for rishu

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