give is cot A=8 find sin A and sec A
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sinA =1/√65
and cosA=8/√65
and cosA=8/√65
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Cot A = 8 = b/p
So base =8x and perpendicular length =x
hypotenuse =[ (8x)²+x²]½ =(65)½x
SinA= p/h = x/(65)½x =1/65)½
SecA =(65)½x /8x =(65)½/8
So base =8x and perpendicular length =x
hypotenuse =[ (8x)²+x²]½ =(65)½x
SinA= p/h = x/(65)½x =1/65)½
SecA =(65)½x /8x =(65)½/8
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