Give maximum value of the energy associated with a capacitor in an L-C oscillator?Answer the given question in brief.
Answers
Answered by
1
If the charge in a capacitor is maximum, there is no current in the circuit and the energy stored in the inductor is zero then,
Total energy = U = Electric energy = ½ Q^2/C
Since the total energy = electric energy = magnetic energy
Magnetic Energy = ½ Q^2/C
U = ½ Q^2/C + ½ Q^2/C
U = Q^2/C
Similar questions