Physics, asked by jaat20687, 1 month ago

give me a answer? fast and correct only​

Attachments:

Answers

Answered by singhanshuman1020
0

Answer:

Magnetic field due to loop P,

Bp = 3u/2r (along x-axis)

Magnetic field due to loop Q,

Bq = 4u/2r (along y-axis)

(where u = mu-not, permeability of free space)

Net magnetic field will be the vector sum of these two,

B^2 = Bp^2 + Bq^2 +2(Bp)(Bq)Cos(90)

B^2 = (9+16)(u/2r)^2

B = 5u/2r

Like and Mark as Brainliest, it really motivates!

Similar questions