Physics, asked by jaat20687, 6 days ago

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Answered by singhanshuman1020
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Answer:

Magnetic field due to loop P,

Bp = 3u/2r (along x-axis)

Magnetic field due to loop Q,

Bq = 4u/2r (along y-axis)

(where u = mu-not, permeability of free space)

Net magnetic field will be the vector sum of these two,

B^2 = Bp^2 + Bq^2 +2(Bp)(Bq)Cos(90)

B^2 = (9+16)(u/2r)^2

B = 5u/2r

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