give me a method to solve this question and that is q.no 10
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write distance formula
(x-a)^2 +y^2 = (a+x)^2
x^2+a^2-2ax+y^2=a^2 +x^2 +2ax
thus, y^2 = 4ax
(x-a)^2 +y^2 = (a+x)^2
x^2+a^2-2ax+y^2=a^2 +x^2 +2ax
thus, y^2 = 4ax
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