Physics, asked by akhilhpr43241, 11 months ago

give me all formulas of light- reflection and refraction class 10

Answers

Answered by chiranjeevikt2004
43

The formula s are below

Attachments:
Answered by dikshaagarwal4442
2

Answer:

  • Mirror :

1. R = radius of curvature , f = focal length. then R = 2f

2. u = object distance, v =  image distance, f = focal length

    Mirror formula: \frac{1}{v} +\frac{1}{u} = \frac{1}{f}

3. Magnification, m = \frac{height of image(h')}{height of object(h)}  =- \frac{v}{u}

4. In case of reflection, angle of incidence(i) = angle of reflection(r)

  • Refraction:

1. From the second law of refraction, \frac{sin i}{sin r} = constant

  here i = angle of incidence and r = angle of refraction.

2. Refractive index = n

  n = \frac{speed of light in medium 1}{speed of light in medium 2} = \frac{v1}{v2}

  If, 1st medium is air and v is speed of light in second medium then we can write, n = \frac{c}{v}

  • Lens:

1.  u = object distance, v =  image distance, f = focal length

    Mirror formula: \frac{1}{v} -\frac{1}{u} = \frac{1}{f}

2. Magnification, m = \frac{height of image(h')}{height of object(h)}  = \frac{v}{u}

3. Power of lens, P = \frac{1}{f}

Explanation

Unit: (i) u, v, f all are measured in 'metre(m)' unit.

        (ii) n and m has no unit.

        (iii) The unit of P is 'dioptre (D)'.

Sign: In case of mirror and lens same sign convention is used.

that is: (i) The principal axis is taken as 'x' axis and centre as origin.

           (ii) The heights above principal axis are "+ve" and the heights below principal axis are "-ve".

           (iii) The right side of the centre is "+ve" and the left side of the centre is considered as "-ve".

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