Math, asked by TheCommonBoy, 1 year ago

Give me all the algebraic identities?

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Anonymous: ___k off

Answers

Answered by honey072
4

here are all your algebraic identities

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Swarup1998: Nice work!
Answered by Anonymous
7

Answer:-

What are  algebraic identities?

Algebraic identities are equalities which remain true  to solve problems in Math. They are  used to rewrite expressions in different ways.

All the Algebraic identities are:-

(a + b)² = a² + 2 ab + b²

 

(a - b)² = (a + b)² - 4 ab

a² - b² = (a + b) (a - b)

 

(x+a) (x+b) =x² + (a + b) x+a b

(a + b)² = (a - b)² + 4 ab

(a - b)² = a² - 2 ab + b²

(a-b)³=a³-3a²b+3ab²-b³

(a-b)³=a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²-ab+b²)

a³-b³= (a-b)(a²+ab+ b²)

a³-b³=(a-b)³ +3ab(a-b)

(a+b+c)²= a²+b²+c² +2ab+2bc+2ca

(a+b-c)²=a²+b²+c² +2ab-2bc-2ca

(a-b+c)²= a²+b²+c²-2ab-2bc+2ca

(a-b-c)²= a²+b²+c²-2ab+2bc-2ca

a² + b² = (a - b)² + 2ab

a² +  b²=½ [(a+b)²-(a-b)²]

ab = ¼[(a+b)²- (a - b)²]

(a + b + c)³ = a³ + b³ + c³ + 3a²b + 3a²c + 3ab²+3b²c + 3ac² + 3bc² + 6abc

(a - b - c)³ = a³ - b³ - c³ - 3a²b - 3a²c + 3ab² + 3b²c + 3ac² - 3bc² + 6abc


ranjanalok961: good
Swarup1998: Nice work!
Anonymous: thanks sir
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