Question

Give me ans fast and solve it​

Answer 1

answer

Step-by-step explanation:

solution

1). ∆PQB and ∆ PBC have same height PQ areas of triangle with equal height are proportional to their corresponding bases

A( ∆PQB). / A(∆PBC). = QB/BC

2). ∆PBC and ∆ ABC have same base BC area of triangle with equal bases are proportional to thir corresponding height A(∆PBC)/ A(∆ABC)= PQ/ AD

3) ∆ ABC and ∆ADC have same height AD areas of triangle with equal height are proportional to their corresponding bases

A(∆ABC)/A(∆ADC)= BC/DC

4. ratio of areas of two triangle is equal to the ratio of the product of their bases and corresponding height

A(∆ABC)/A(∆ADC)= DC× AD / QC× PQ

answer = 1). A(∆PQB) / A(∆PBC) = QB/ BC

2). A(∆PBC) / A(∆ABC) = PQ/ AD

3). A(∆ABC) / A(∆ADC) = BC/ DC

4). A(∆ADC) / A(∆PQC) = DC× AD / QC×PQ

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