Question

give me ans please ​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=14400\:km/h^{2}}}}$

$\green{\tt{\therefore{Acceleration=1.1\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Final \: velocity(v) = 40 \: km/h \\ \\ \tt: \implies Time(t) = 10 \: seconds \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Acceleration(a) = ?$

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: km/h\\ \\ \tt \circ \: Final \: velocity = 40 \: km/h \\ \\ \tt \circ \: Time = \frac{10}{3600} = \frac{1}{360} \: h\\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 40 = 0 + a \times \frac{1}{360} \\ \\ \tt: \implies 40 = a \times \frac{1}{360} \\ \\ \tt: \implies 40 \times 360 = a \\ \\ \green{\tt: \implies a = 14400 \: km/{h}^{2} } \\ \\ \bold{Acceleration \: in \: m/{s}^{2} } \\ \tt \circ \: Final \: velocity = 40 \times \frac{5}{18} = \frac{100}{9} \: m/s \\ \\ \tt \circ \: Time = 10 \: s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies \frac{100}{9} = 0 + a \times 10 \\ \\ \tt: \implies \frac{100}{9 \times 10} = a \\ \\ \tt: \implies a = \frac{10}{9} \\ \\ \green{\tt: \implies a = 1.1 \: {m/s}^{2} }$

Answer 2

Given:-

The bus starts from rest and attains a velocity of 40 km/h.

To find:-

The acceleration of the bus in m/s² and km/h².

Solution:-

Bus starts from rest , it means initial velocity of bus , u = 0

Bus attains 40 km/h velocity after 10 s.

final velocity of bus , v = 40 km/h = 40 × 5/18 m/s [ we know, 1 km/h = 5/18 m/s ]

v = 100/9 m/s

Time taken by bus , t = 10 s

Using the formula:

v = u + at

From above , v = 100/9 m/s , u = 0 and t = 10 s

Now,

100/9 = 0 + a × 10

⇒ 100/9 = 10a

⇒ a = 10/9 m/s²

Hence, acceleration of bus in m/s² = 10/9 m/s² = 1.11 m/s².

Now, acceleration of bus in km/h²

v = 40 km/h ,

u = 0  

t = 10 s = 10/3600 hr = 1/360 hr

Now, from the formula ,

v = u + at

⇒40 = 0 + a × 1/360

⇒40 = a/360

⇒a = 40 × 360 = 14400 km/h²

∴Hence, the solution is:

(a) 14400 km/h²

(b) 1.11 m/s²