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Therefore ur is this,
A=5N
B=3N
For angle 0 degree.
=> (A-B)=√A^2 +B^2 -2ABcos theta
=√25+9-30
=√4
=2N
For angle 180°
=> (A-B) =√34+30
=√64 =8N
for angle 90°
=> (A-B) =√34 -30×0
=√34 N
for angle 60°
=> (A-B) =√34-30×1/2
√19 N.
Hope this help
A=5N
B=3N
For angle 0 degree.
=> (A-B)=√A^2 +B^2 -2ABcos theta
=√25+9-30
=√4
=2N
For angle 180°
=> (A-B) =√34+30
=√64 =8N
for angle 90°
=> (A-B) =√34 -30×0
=√34 N
for angle 60°
=> (A-B) =√34-30×1/2
√19 N.
Hope this help
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