Question

give me answer and get 50 points

Answer 1

Hey! ! !

Mate :-

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Solution :-

Sum of exterior angle of triangle = 360

3x + 2x + 4x = 360

9x = 360

:- x = 360/9

Her x = 40

So that :-

3x = 3 × 40 = 120

2x = 2 × 40 = 80

4x = 4 × 40 = 160

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Answer 2

Heya‼

We have to find the value of x .

• angle PBA = angle QBP + angle QBA
=> 180° = 2x + angle QBA
=> angle QBA = 180° – 2x ...(1)

• angle QCB = angle QCA + angle ACB
=> 180° = 3x + angle ACB
=> angle ACB = 180° – 3x ...(2)

• angle RAC = angle RAP + angle BAC
=> 180° = 4x + angle BAC
=> angle BAC = 180° – 4x


Now, by angle sum property :-

angle QBA + angle ACB + angle BAC = 180°
[ Sum of angles of a ∆ is 180° ]

=> (180° – 2x ) + (180° – 3x) + (180° – 4x) = 180°

=> 540° – 9x = 180°

=> 540° – 180° = 9x

=> 360° = 9x

=> x = 360 / 9

=> x = 40°


Therefore,
angle QBP i.e., 2x = (40×2) = 80° ,
angle QCA i.e., 3x = (40×3) = 120° and
angle RAP i.e., 4x = (40×4) = 160°