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20 m/s and 20 m is the answer derived using the formulas: v=u+at and v^2=u^2+2as.
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Answer:
20m/s and 20m
Explanation:
Using the equations of motion
v = u + at
where,
v = final velocity
u = initial velocity
a = Acceleration due to gravity
t = time required to reach final velocity
As per given data
t = 2 sec, g=10m/s²
A ball falls off a table implies that u=0 m/s (initially at rest)
therefore v = 0 + 10*2 = 20 m/s
Velocity of ball on reaching ground = 20 m/s
According to third equations of motion,
s = ut + 1/2 at²
s = 0 + 1/2*10(2)²
= 40/2
= 20 m
Height of table = 20 m
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